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| I am trying read filelist.log and strip out all file attributes and
print only the full path filname to output.log. The command (2 below)
I tried does not generate the appropriate output. (NOTE: I even tried
to issue cut without the -d switch, since tab is the default delimiter
for cut, it still doesn't work) What am I doing wrong here?
Here is what I issued on the command line:
cut -f11 -d ' ' filelist.log > output.log
OR since some paths come with directory / file names with space. I
would use this also:
cut -f 11-20 -d ' ' filelist.log > output.log
Here is my filelist.log:
23151931 43 -rwxrw-r-- 1 www www 43520 Oct 8 2004 /
export/home/qa/Utils/All 3rd Party Version/Docs/thirdparty.doc
33219855 3048 -rwxrw-r-- 1 www www 3109936 Jun 18 2004 /
export/home/qa/Utils/All 3rd Party Version/Popular Versions/VPN
_PPC/movianvpn-3.05-ppc2002.exe
Here is my output.log
23151931 43 -rwxrw-r-- 1 www www 43520 Oct 8 2004 /
export/home/qa/Utils/All 3rd Party Version/Docs/thirdparty.doc
33219855 3048 -rwxrw-r-- 1 www www 3109936 Jun 18 2004 /
export/home/qa/Utils/All 3rd Party Version/Popular Versions/VPN
_PPC/movianvpn-3.05-ppc2002.exe
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