| Author |
loop and list with bash
|
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| Eric Belhomme 2004-10-02, 9:13 pm |
| Hi,
I'm trying to write a little bash (version 2.05a.0 on GNU/Linux Debian
woody) script that list à directory tree to change user/rights permission :
#!/bin/bash
for item in `ls -AlQ /mnt/data/divx | grep -v total`
do
echo $item
done
I would get into the variable $item something like that :
-rwxr-xr-x 1 rico staff 270193540 sep 4 2003 "a_file.txt"
But in reality each line generated by ls command is splitted into 9 list
element, so I get for each loop iteration :
-rwxr-xr-x
1
rico
staff
....
So what sould I do to get only 1 list item for each line reported by ls
command ?
regards,
--
Rico
| |
| Stephane CHAZELAS 2004-10-02, 9:13 pm |
| 2004-09-30, 08:55(+00), Eric Belhomme:
[...]
> #!/bin/bash
>
> for item in `ls -AlQ /mnt/data/divx | grep -v total`
> do
> echo $item
> done
>
> I would get into the variable $item something like that :
> -rwxr-xr-x 1 rico staff 270193540 sep 4 2003 "a_file.txt"
[...]
IFS=$'\n'
set -f
for item in $(ls -AlQ /mnt/data/divx | tail +2); do
printf '%s\n' "$item"
done
Note that the -Q option doesn't help bash in anyway to handle
filenames with special characters in them.
--
Stephane
| |
| Eric Belhomme 2004-10-02, 9:13 pm |
| Stephane CHAZELAS <this.address@is.invalid> wrote in
news:slrnclnni6.23k.stephane.chazelas@spam.is.invalid:
> IFS=$'\n'
damn ! this single sentence resolve my problem ! What's that ? what does it
mean ?
> set -f
and that ?
> Note that the -Q option doesn't help bash in anyway to handle
> filenames with special characters in them.
>
Sure, but it helps me to handle filenames with spaces...
thanks for your help ;)
regards,
--
Rico
| |
| Eric Belhomme 2004-10-02, 9:13 pm |
| Stephane CHAZELAS <this.address@is.invalid> wrote in
news:slrnclns6l.23k.stephane.chazelas@spam.is.invalid:
thanks for this very instructive course  )
As I wonder you're french, maybe can you suggest a good book for bash
scripting (and sed/awk use) ?
> [...]
>
> How?
>
ls -QAl ./ | cut -d "\"" -f 2
And I just get file name with spaces
--
Rico
| |
| Stephane CHAZELAS 2004-10-02, 9:13 pm |
| 2004-09-30, 07:37(-04), Bill Marcum:
[...]
[...][vbcol=seagreen]
> Check Google for "comp.unix.shell Frequently Asked Questions".
>
> ls -AlQ /mnt/data/divx | grep -v total | while read item
> or
> ls -AlQ /mnt/data/divx | grep -v total |\
> while read permission links owner group size month day year_or_time filename
[...]
With that in mind that any variable assigned inside the while
loop will be lost afterwards.
Also note that the second one doesn't work correctly for
symbolic links.
Also note the "-r" option to read otherwise read does
extra-processing on the read input.
Also note that every command within the loop won't have their
stdin connected to the terminal anymore (or whatever it was
before) but from the pipe.
{ ls -ALlQ /mnt/data/divx | tail +2 | \
while read <&4 -r permission links owner group \
size month day year_or_time filename
do ...
done 4<&0 <&3 3<&-; } 3<&0
(untested)
--
Stephane
| |
| Paul Jarc 2004-10-03, 7:47 am |
| Eric Belhomme <eric.belhomme_NOSPAM@free.fr.invalid> wrote:
> I'm trying to write a little bash (version 2.05a.0 on GNU/Linux Debian
> woody) script that list à directory tree to change user/rights permission :
Is "chmod -R" what you're looking for?
> So what sould I do to get only 1 list item for each line reported by ls
> command ?
for item in /mnt/data/divx/* /mnt/data/divx/.[!.]* /mnt/data/divx/..?*; do
lsdata=`ls -ld "$item"` && ...
done
paul
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