Unix Shell - Re: bash: var contains full line. How to input this data with spaces

Author

Re: bash: var contains full line. How to input this data with spaces

Ed Morton

2005-03-30, 5:58 pm

Ed Morton wrote:
<snip>
> BEGIN{FS="";nv=1}{
> for (i=1;i<=NF;i++) {
> if ( $i == "\"" ) {
> quoted = !quoted
> $i = "\\" $i
> }
> if ((quoted) || ($i != " ")) {
> var = var $i
> } else if (($i == " ") && (var != "")) {
> printf "VAR%s=\"%s\"\n",++nv,var
> var = ""
> }
> }
> }END{ printf "VAR%s=\"%s\"\n",++nv,var }

And, if you want to handle tabs, etc. in the same way as the above
handles just space characters, just change it to:

BEGIN{FS="";nv=1}{
for (i=1;i<=NF;i++) {
if ( $i == "\"" ) {
quoted = !quoted
$i = "\\" $i
}
if ((quoted) || ($i !~ /[[:blank:]]/)) {
var = var $i
} else if (($i ~ /[[:blank:]]/) && (var != "")) {
printf "VAR%s=\"%s\"\n",++nv,var
var = ""
}
}
}END{ printf "VAR%s=\"%s\"\n",++nv,var }

Ed.