Unix Shell - Simple date validation

Author

Simple date validation

Derk

2006-10-20, 7:21 am

I want to perfom a simple date validation on a variable. I have got the
following script working, but I want it to fail if it does not match the
pattern

How do I reverse the test

--------------------------------------

case $p1 in
[0-3][0-9]/[0-1][0-9]/[0-9][0-9])
echo "Invalid"
exit 1 ;;
esac

... continue processing

--------------------------------------

Thanks

Derrick

Ed Morton

2006-10-20, 1:22 pm

Derk wrote:
> I want to perfom a simple date validation on a variable. I have got the
> following script working, but I want it to fail if it does not match the
> pattern
>
> How do I reverse the test
>
> --------------------------------------
>
> case $p1 in
> [0-3][0-9]/[0-1][0-9]/[0-9][0-9])
> echo "Invalid"
> exit 1 ;;
> esac

case $p1 in
[0-3][0-9]/[0-1][0-9]/[0-9][0-9]) : ;;
*)
echo "Invalid"
exit 1 ;;
esac

Regards,

Ed.