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Home > Archive > BizTalk Server General > November 2004 > How I get the source filename and extract character of its string
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| Author |
How I get the source filename and extract character of its string
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| Sendam? Luque 2004-11-26, 7:47 am |
| I have a map and a field of the target schema is composed for three
characters, which are of the name of the source file.
How I get these characters?
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| Martijn Hoogendoorn 2004-11-29, 5:52 pm |
| On 26 Nov 2004 06:05:03 -0800, Sendam? Luque wrote:
> I have a map and a field of the target schema is composed for three
> characters, which are of the name of the source file.
> How I get these characters?
Hi Sendam,
Could you explain your issue in some more detail? Right now, it sounds like
you could simply drag a line from the source schema into the target schema
and you would be done.
HTH,
Martijn Hoogendoorn
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| Sendam? Luque 2004-11-30, 2:46 am |
| Martijn Hoogendoorn <martijn.hoogendoorn@macaw.nl> wrote in message news:<1d8owvhvioarz$.1gmi5q36ov98k$.dlg@40tude.net>...
> On 26 Nov 2004 06:05:03 -0800, Sendam? Luque wrote:
>
>
> Hi Sendam,
>
> Could you explain your issue in some more detail? Right now, it sounds like
> you could simply drag a line from the source schema into the target schema
> and you would be done.
>
> HTH,
>
> Martijn Hoogendoorn
Hi, well, I have a map with its source schema and target schema. I
need three characters which belong to the name of the source file.
With these characters, I have to assign to a field of the target
schema. I am trying get it with a orchestration but I am having many
problems. I donīt know how I get the name of the source file.
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| Greg Forsythe 2004-11-30, 7:46 am |
| Construct Message
Transform Shape (inputmessage -> myNewMessage)
Message Assignment Shape
myNewMessage.myDistinguishedField = FILE.ReceivedFileName;
Greg
"Sendam? Luque" <sendami_luque@hotmail.com> wrote in message
news:8f79bbe5.0411300018.50dd82d8@posting.google.com...
> Martijn Hoogendoorn <martijn.hoogendoorn@macaw.nl> wrote in message
news:<1d8owvhvioarz$.1gmi5q36ov98k$.dlg@40tude.net>...
like[vbcol=seagreen]
schema[vbcol=seagreen]
>
> Hi, well, I have a map with its source schema and target schema. I
> need three characters which belong to the name of the source file.
> With these characters, I have to assign to a field of the target
> schema. I am trying get it with a orchestration but I am having many
> problems. I donīt know how I get the name of the source file.
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