BizTalk Server Orchestration - How can I split a message in more message?

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Author How can I split a message in more message?
Eva

2004-10-27, 2:47 am

Hallo,
I receive a message, that contents periodic information,
f.e:
....
<Person>
<id>1</id>
<name>XY1</name>
...
</Person>
<Person>
<id>1</id>
<name>XY1</name>
...
</Person>
....
I would like to create so many new messages with the Person datas, how many
Person exists.
Can somebody help me?
Thanks!

Ruslan Yakushev [MSFT]

2004-10-29, 8:46 pm

You would need to use an XML disassembler and define the envelope and
document schemas. Document schemas need to correspond to the <person> node
in your document.

For example of how to use envelopes and break up document into smalled docs
you can take a look at the AssemblerDisassembler SDK sample.
--------------------
>Thread-Topic: How can I split a message in more message?
>thread-index: AcS7+WzpboDtB24NTTGMZvogdR5pkg==
>X-WBNR-Posting-Host: 192.35.17.30
>From: =?Utf-8?B?RXZh?= <Eva@discussions.microsoft.com>
>Subject: How can I split a message in more message?
>Date: Wed, 27 Oct 2004 00:49:02 -0700
>Lines: 20
>Message-ID: <FD0CD500-68C3-4AA8-AB24-2306E0FAEC57@microsoft.com>
>MIME-Version: 1.0
>Content-Type: text/plain;
> charset="Utf-8"
>Content-Transfer-Encoding: 7bit
>X-Newsreader: Microsoft CDO for Windows 2000
>Content-Class: urn:content-classes:message
>Importance: normal
>Priority: normal
>X-MimeOLE: Produced By Microsoft MimeOLE V6.00.3790.0
>Newsgroups: microsoft.public.biztalk.orchestration
>NNTP-Posting-Host: TK2MSFTNGXA03.phx.gbl 10.40.1.29
>Path: cpmsftngxa10.phx.gbl!TK2MSFTNGXA03.phx.gbl
>Xref: cpmsftngxa10.phx.gbl microsoft.public.biztalk.orchestration:8818
>X-Tomcat-NG: microsoft.public.biztalk.orchestration
>
>Hallo,
>I receive a message, that contents periodic information,
>f.e:
>...
> <Person>
> <id>1</id>
> <name>XY1</name>
> ...
> </Person>
> <Person>
> <id>1</id>
> <name>XY1</name>
> ...
> </Person>
>...
>I would like to create so many new messages with the Person datas, how

many
>Person exists.
>Can somebody help me?
>Thanks!
>
>


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