hi

i would like to be able to do:

-t 18 -f a1 a2 a3....

i don't know how much parameter there is for f....

are there a way to do that?

the code:

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>


int
main (int argc, char **argv)
{
int c;
int timer=0;
int cptTime=0;
char *ifile;
int index;
extern char *optarg;
extern int optind, optopt;

printf("argc: %d\n", argc);

while ((c = getopt(argc, argv, "t:f")) != -1) {
switch(c) {
case 't':
timer=1;
cptTime = atoi(optarg);
break;
case 'f':
ifile = optarg;
break;
}
}

if(timer==1)
while(1==1)
{


}

for (index = optind; index < argc; index++)
printf ("Non-option argument %s\n", argv[index]);
return 0;
}



thanks

[ Post a follow-up to this message ]

collinm <collinm@laboiteaprog.com> wrote:
> hi
>
> i would like to be able to do:
>
> -t 18 -f a1 a2 a3....

Standard convention is to use the form:

-t 18 -f a1 -f a2 -f a3

Or

-t 18 -f "a1 a2 a3"

Though the latter means you have to parse it yourself.

Otherwise, I don't think getopt() will work for you unless '-f' will always
be the last argument given--so you know you could traverse the remaining
indices in argv. But, that's quite ugly and it gets worse from there.

- Bill

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