Dim gallery As ResourceGallery =
CmsHttpContext.Current.Searches.GetByGuid(UserMenuLocalTree.GetNodeFromIndex
(UserMenuLocalTree.SelectedNodeIndex).ID())

Dim AppContext As CmsApplicationContext = New
CmsApplicationContext
(Microsoft.ContentManagement.Publishing.CmsHttpContext.Current.User.ServerAc
countName,
"abc@123", PublishingMode.Update)



'AppContext. AuthenticateAsCurrentUser(PublishingMode
.Update)
Dim gallery As ResourceGallery =
CmsHttpContext.Current.Searches.GetByGuid(UserMenuLocalTree.GetNodeFromIndex
(UserMenuLocalTree.SelectedNodeIndex).ID())
If gallery.CanCreateResources Then

gallery.CreateResource(txtMainImg.PostedFile.FileName)
Else
errMsg = "cant't create"
End If

*******************

when i execute above code i got access denied error.how to solve that
error. Any one pls help me.

[ Post a follow-up to this message ]

Hi,

you have created an applicaiton context in update mode but you are trying to
upload the item using the CmsHttpContext which is most likely not in update
mode.
That will not work.

You need to retrieve the gallery using the application context and not using
the CmsHttpContext then the upload will work.

Cheers,
Stefan

--
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----------------------


"dsen_25" <dsen_25@yahoo-dot-com.no-spam.invalid> wrote in message
news:TOadnUml47uhyqzeRVn_vA@giganews.com...
> Dim gallery As ResourceGallery =
> CmsHttpContext.Current.Searches.GetByGuid(UserMenuLocalTree.GetNodeFromInd
ex(UserMenuLocalTree.SelectedNodeIndex).ID())
>
>                Dim AppContext As CmsApplicationContext = New
> CmsApplicationContext
> (Microsoft.ContentManagement.Publishing.CmsHttpContext.Current.User.Server
AccountName,
> "abc@123", PublishingMode.Update)
>
>
>
> 'AppContext. AuthenticateAsCurrentUser(PublishingMode
.Update)
>                Dim gallery As ResourceGallery =
> CmsHttpContext.Current.Searches.GetByGuid(UserMenuLocalTree.GetNodeFromInd
ex(UserMenuLocalTree.SelectedNodeIndex).ID())
>                If gallery.CanCreateResources Then
>
> gallery.CreateResource(txtMainImg.PostedFile.FileName)
>                Else
>                    errMsg = "cant't create"
>                End If
>
> *******************
>
> when i execute above code i got access denied error.how to solve that
> error. Any one pls help me.
>

[ Post a follow-up to this message ]

Thanks.Now it is working.

[ Post a follow-up to this message ]