How in orchestration to get the outgoing file name for a message sent to Fil
e
Send Port and file mask as %MessageID%.xml ?

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Not sure, but maybe you can generate your own filename, using dynamic ports,
i.e. generate your own GUID and set the filename in parentheses after the
messagename like this:
msgOrderCheckInventoryRequest(FILE.ReceivedFileName) =
strYourGeneratedFileName;

(It's a little weird that use use ReceiveFileName instead of SendFileName,
but did it a long time ago, and if I remember properly, it works).



Neal Walters
http://Biztalk-Training.com

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Thanks Neal, it seems to be the only way to do this. Once you set
FILE.ReceiveFileName you have to use macros %SourceFileName% in the send por
t
settings.

"Neal Walters" wrote:

> Not sure, but maybe you can generate your own filename, using dynamic port
s,
> i.e. generate your own GUID and set the filename in parentheses after the
> messagename like this:
>    msgOrderCheckInventoryRequest(FILE.ReceivedFileName) =
> strYourGeneratedFileName;
>
> (It's a little weird that use use ReceiveFileName instead of SendFileName,
> but did it a long time ago, and if I remember properly, it works).
>
>
>
> Neal Walters
> http://Biztalk-Training.com
>

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