03-15-06 10:55 PM
Hi
I was doing a simple test of the speed of a "maths" operation and when I
tested it I found that removing the loop that initialises the data array
for the operation caused the whole program to spend twice the time to
complete. If the loop is included it takes about 7.48 seconds to
complete, but when removed it takes about 11.48 seconds.
Does anybody have a suggestion as to why this is so and whether I can
trust the results of the code as it is below?
(I tried declaring total and data as unsigned, because of time taken on
overflows as someone suggested, but it did not affect it)
/tom
The code was compiled on linux 2.6.3 with gcc 3.3.2 and glibc 2.2.3
compiler arguments are "-O2 -Wall -D_LARGEFILE64_SOURCE -std=gnu99"
#include <stdio.h>
#include <stdlib.h>
#include <sys/time.h>
int main(int argc, char *argv[])
{
int total = 0;
int count = 65500;
signed int data[count];
/* Initialising array loop */
for(int c=0; c<count; c++) {
data[c]=1+(int) (2000000000.0*rand()/(RAND_MAX+1.0));
}
struct timeval start_time;
struct timeval end_time;
gettimeofday(&start_time, NULL);
for(int d=0; d<50000; d++) {
for(int c=0; c<count; c++) {
total += data[c];
}
}
gettimeofday(&end_time, NULL);
double t1=(start_time.tv_sec*1000)+(start_time.tv_usec/1000.0);
double t2=(end_time.tv_sec*1000)+(end_time.tv_usec/1000.0);
printf("Elapsed time (ms): %.6lf\n", t2-t1);
printf("Total: %u\n", total);
return(0);
}
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