Hi ,
I am new to unix .
I have  a file to read and after reading each line I want to strip off
the first 3 characters and store in another variable.
Cut command cuts the first 3 characters but I do not how to get the
rest of letters.
For ex:
I have  a line  XXX_JOBNAME
Here is the code
cat jobs.txt |cut -c1-4
This prints XXXX_.
I want JOBNAME to be printed .But length of JOBNAME differs in each
line.


#Logic

ext=".ksh"
for line in `cat ~/jobs.txt`
do
echo $line
#remove the XXX_
#put the cut logic here after ripping of 3
characters and strore in another variale "job"

#concanat .ksh to each job = $job
job="$line$ext"
echo $job
#copy from SRC to taget
#cp ~/src/job.ksh ~/target
done


pls guide.
Thanks

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nicetom786@yahoo.com wrote:

> I have  a file to read and after reading each line I want to strip off
> the first 3 characters and store in another variable.
[...]
> cat jobs.txt |cut -c1-4

cat jobs.txt | cut -c5-

--
mail1dotstofanetdotdk

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<nicetom786@yahoo.com> wrote in message
news:1159461178.490764.15280@m7g2000cwm.googlegroups.com...
> Hi ,
> I am new to unix .
> I have  a file to read and after reading each line I want to strip off
> the first 3 characters and store in another variable.
> Cut command cuts the first 3 characters but I do not how to get the
> rest of letters.
> For ex:
> I have  a line  XXX_JOBNAME
> Here is the code
> cat jobs.txt |cut -c1-4
> This prints XXXX_.
> I want JOBNAME to be printed .But length of JOBNAME differs in each
> line.

cat jobs.txt | cut -c5-

>
>
> #Logic
>
> ext=".ksh"
> for line in `cat ~/jobs.txt`
>        do
>                        echo $line
>                        #remove the XXX_
>                        #put the cut logic here after ripping of 3
> characters and strore in another variale "job"
>
>                        #concanat .ksh to each job = $job
>                        job="$line$ext"
>                        echo $job
>                        #copy from SRC to taget
>                        #cp ~/src/job.ksh ~/target
>         done
>
>
> pls guide.
> Thanks
>
--
Fred L. Kleinschmidt
Boeing Associate Technical Fellow
Technical Architect, Software Reuse Project

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Bjorn Reese <breese@see.signature> writes:

> nicetom786@yahoo.com wrote:
> 
> [...] 
>
> cat jobs.txt | cut -c5-

UUOC

--
Måns Rullgård
mru@inprovide.com

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nicetom786@yahoo.com writes:

> I have  a file to read and after reading each line I want to strip off
> the first 3 characters and store in another variable.
> Cut command cuts the first 3 characters but I do not how to get the
> rest of letters.
> For ex:
> I have  a line  XXX_JOBNAME
> Here is the code
> cat jobs.txt |cut -c1-4
> This prints XXXX_.
> I want JOBNAME to be printed .But length of JOBNAME differs in each
> line.
>
>
> #Logic
>
> ext=".ksh"
> for line in `cat ~/jobs.txt`

Are you aware 'line' is misleading here? You don't read each line but
rather each word of the given file.

>         do
>                         echo $line
>                         #remove the XXX_
>                         #put the cut logic here after ripping of 3
> characters and strore in another variale "job"
>
>                         #concanat .ksh to each job = $job
>                         job="$line$ext"
>                         echo $job
>                         #copy from SRC to taget
>                         #cp ~/src/job.ksh ~/target
>          done

If you need to read the lines anyway you can omit cut as it introduces
another fork() which is not needed, ie:

#v+
while read line; do
cp -- ~/src/${line#????}.ksh" ~/target/
done <file-with-jobs
#v-

If you are sure the lines do not contain any funky characters and have
GNU mv, you can use something possibly faster:

#v+
cd ~/src
sed -ne 's/^....\(.*\)$/\1.ksh/p' <file-with-jobs | \
xargs mv --target-directory=~/target --
#v-


--
Best regards,                                         _     _
.o. | Liege of Serenly Enlightened Majesty of      o' \,=./ `o
.o | Computer Science,  Michal "mina86" Nazarewicz   (o o)
ooo +--<mina86*tlen.pl>--<jid:mina86*jabber.org>--ooO--(_)--Ooo--

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