I am trying read filelist.log and strip out all file attributes and
print only the full path filname to output.log.  The command (2 below)
I tried does not generate the appropriate output.  (NOTE: I even tried
to issue cut without the -d switch, since tab is the default delimiter
for cut, it still doesn't work) What am I doing wrong here?

Here is what I issued on the command line:

cut -f11 -d '  ' filelist.log > output.log

OR since some paths come with directory / file names with space.  I
would use this also:

cut -f 11-20 -d '  ' filelist.log > output.log


Here is my filelist.log:

23151931   43 -rwxrw-r--  1 www      www         43520 Oct  8  2004 /
export/home/qa/Utils/All 3rd Party Version/Docs/thirdparty.doc
33219855 3048 -rwxrw-r--  1 www      www       3109936 Jun 18  2004 /
export/home/qa/Utils/All 3rd Party Version/Popular Versions/VPN
_PPC/movianvpn-3.05-ppc2002.exe

Here is my output.log

23151931   43 -rwxrw-r--  1 www      www         43520 Oct  8  2004 /
export/home/qa/Utils/All 3rd Party Version/Docs/thirdparty.doc
33219855 3048 -rwxrw-r--  1 www      www       3109936 Jun 18  2004 /
export/home/qa/Utils/All 3rd Party Version/Popular Versions/VPN
_PPC/movianvpn-3.05-ppc2002.exe

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