Set/change OutboundTransportLocation property
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    Set/change OutboundTransportLocation property  
Cecilie


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05-12-04 01:21 AM

Hi,

I want to set/change the OutboundTransportLocation property. I mean, I want 
to set destination folder and filename in runtime.

The case :
I receive flatfiles in several folder. Each system has its own folder. The f
iles must be picked up, mapped from one flatfile format to an another and se
nt to a destination folder. The destination filename must be on this format 
: <two character system ini
tials>YYYYMMDD<one digit counter>.sdv (sample : IM200405110.sdv). Receive ma
x 10 filer per day. Info about destination folder must be read from registry
. The filename must be available in the map.

I plan to solve it like this :
Get flatfile from receive folder, create new filename with db interactions i
n flat file receive pipeline (need to do db interactions because info about 
the current counter value is stored in db), read destination path/folder fro
m registry in receive pipel
ine, set OutboundTransportLocation property = path + new filename in receive
 pipeline, set promoted schema property = new filename in receive pipeline, 
map file (use promoted property/field when mapping), send file to destinatio
n folder with new filename
through a flat file send pipeline.

Questions :
1. Is it ok to do it like this?
2. How do I read/set the OutboundTransportLocation property in a receive pip
eline? Method? What namespace?
3. Must I use "Dynamic one-way-port" in the send port when changing/setting 
the OutboundTransportLocation property?

I really hope you can help me!
I use VB.Net so if it's possible to get samples in VB.Net it would be great 


Regards,
Cecilie





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