Simple problem.  I want to eject a CD from a drive.  After plenty of
tooling around the only reliable way I could do this is to utilize the
raw device number (or block device number).

I'm using the Solaris SUNWcdrw package to burn disks so I decided to use
it to extract the raw device number using 'cdrw -l'.  Ex: Parse out
"/dev/rdsk/c0d0t0s0" and do a /usr/bin/eject on that device.
The problem is 'cdrw -l' doesn't always give me the raw device number.
Sometimes it gives me the logical name 'cdrom0'. Fortunately I'm working
on a closed system so I could parse out the /etc/mnttab file to get the
block device for the /cdrom mount point but this would never work in a
real world situation.

Finally my question. How can I always reliably eject a CD from its drive?

Thanks.

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On Dec 7, 3:48 pm, Bender <jnbben...@gmail.com> wrote:
> Simple problem.  I want to eject a CD from a drive.  After plenty of
> tooling around the only reliable way I could do this is to utilize the
> raw device number (or block device number).
>
> I'm using the Solaris SUNWcdrw package to burn disks so I decided to use
> it to extract the raw device number using 'cdrw -l'.  Ex: Parse out
> "/dev/rdsk/c0d0t0s0" and do a /usr/bin/eject on that device.
> The problem is 'cdrw -l' doesn't always give me the raw device number.
> Sometimes it gives me the logical name 'cdrom0'. Fortunately I'm working
> on a closed system so I could parse out the /etc/mnttab file to get the
> block device for the /cdrom mount point but this would never work in a
> real world situation.
>
> Finally my question. How can I always reliably eject a CD from its drive?

If there is more than one CD drive on the system, how will you know
which one to eject?

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fjblurt@yahoo.com wrote:
> On Dec 7, 3:48 pm, Bender <jnbben...@gmail.com> wrote: 
>
> If there is more than one CD drive on the system, how will you know
> which one to eject?

That situation I can guarantee against or at least give the user an
option. After poking around it looks like some ioctl calls with
CDROMEJECT should do the trick but still...

How do I discover the CD device names?

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On 2007-12-07, Bender <jnbbender@gmail.com> wrote:
>
>
> Simple problem.  I want to eject a CD from a drive.  After plenty of
> tooling around the only reliable way I could do this is to utilize the
> raw device number (or block device number).
>
> I'm using the Solaris SUNWcdrw package to burn disks so I decided to use
> it to extract the raw device number using 'cdrw -l'.  Ex: Parse out
> "/dev/rdsk/c0d0t0s0" and do a /usr/bin/eject on that device.
> The problem is 'cdrw -l' doesn't always give me the raw device number.
> Sometimes it gives me the logical name 'cdrom0'. Fortunately I'm working
> on a closed system so I could parse out the /etc/mnttab file to get the
> block device for the /cdrom mount point but this would never work in a
> real world situation.
>
Wait a minute. If 'cdrw -l' returns a mount point, shouldn't you
umount the cdrom before ejecting it?

ls -ld . $(cdrw -l) | awk '/^b/{print $9}'
should list only block device names.

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Bill Marcum wrote:
> On 2007-12-07, Bender <jnbbender@gmail.com> wrote: 
> Wait a minute. If 'cdrw -l' returns a mount point, shouldn't you
> umount the cdrom before ejecting it?
>
> ls -ld . $(cdrw -l) | awk '/^b/{print $9}'
> should list only block device names.

'cdrw -l' returns the raw device name or the logical device
name(cdrom0). The nice thing about this is you can eject an unmounted
CD, one that is blank.  I would like to get the device name because then
I would be able to handle the non-mounted case.
In the case where I wanted to eject a CD only if it were mounted I would
parse out the /etc/mnttab using getmntent and grab the device name that way.

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