I published a tiny little schema as a webservice just to understand the
concept.
The schema only has three fields (poamt, podate, ponum).

I created a Windows form to test on a button-click event.

Dim x As New localhost.DWEasyPO
x.poamt = 500
x.podate = #3/5/2004#
x.ponum = "DWY-001"

Dim ws As New localhost.DwyerWebServicePO
ws.WebMethodPO1(x)     '<--- blows up here
msgbox "okay"

So my understanding is that if it works, it should put an instance of the
message in a receive port, then I could have send ports subscribed to that.
The wizard created a receive location called:
WebService_BizTalkWebServiceDwPO/DWebServicePO with the appropriate SOAP
transport type and web service address.

I'm blowing up in this line of code (from code sample above):
ws.WebMethodPO1(x)

with this exception:
An unhandled exception of type
'System.Web.Services.Protocols.SoapException' occured in
system.web.services.dll.  Additional info: ... Internal SOAP Processing
Failure at Microsoft.Biztalk.WebServices.ServerProxy.Invoke(String
functionName, Object[] parameters, ParamInfo[] in ParamInfos, ParamI
nfo[]
outParamInfos, Int32 bodyPartInex, String bodyType, ArrayList

and the higlighted line of code in theproxy is:
Dim results() as Object = Me.Invoke("WebMethodPO1",
New Object() {DWEasyPO})

Also, when running the publish/wizard, I wasn't sure how to omit the
response from the Request/Response.   I still don't get how submitting a
schema can really have a response.

Thanks in advance,
Neal Walters
http://Biztalk-Training.com

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