Hi,

Is there any way to define exclusive campaigns?

I mean exclude all the items of a particular campaign once its applied. I
think now its excluding only the items required for qualify the campaign
and remaning items are using for other campaigns to qualify.

Three discounts has been defined on a particular product as follows :

Discount 1:  you buy 12 of Product A and you get 2 of Product A free.
(Limit :1, Priority : 30)

Discount 2:  you buy 25 of Product A and you get 5 of Product A free.
(Limit :1, Priority : 20)

Discount 3:  you buy 50 of Product A and you get 12 of Product A free.
(Limit :1, Priority : 10)

Suppose the basket quantiy is 45, then basket
pipeline applying applying discount on 7 items since I think the
"discount 2" and "discount 1" are applying. But we have to give only 5
free quntity for 45 basket items. we want to apply only "discount 2"


Thanks for any help

Ajay

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Check out the tiered discounts section in this blog which may help

http://blogs.msdn.com/yuxiangxu

Sam

ajay_adoor@rediffmail.com (Ajay) wrote in message news:<30ce19b1.0410032234.1316e44c@posting
.google.com>...
> Hi,
>
> Is there any way to define exclusive campaigns?
>
> I mean exclude all the items of a particular campaign once its applied. I
> think now its excluding only the items required for qualify the campaign
> and remaning items are using for other campaigns to qualify.
>
> Three discounts has been defined on a particular product as follows :
>
>    Discount 1:  you buy 12 of Product A and you get 2 of Product A free.
> (Limit :1, Priority : 30)
>
>    Discount 2:  you buy 25 of Product A and you get 5 of Product A free.
> (Limit :1, Priority : 20)
>
>    Discount 3:  you buy 50 of Product A and you get 12 of Product A free.
> (Limit :1, Priority : 10)
>
> Suppose the basket quantiy is 45, then basket
> pipeline applying applying discount on 7 items since I think the
> "discount 2" and "discount 1" are applying. But we have to give only 5
> free quntity for 45 basket items. we want to apply only "discount 2"
>
>
> Thanks for any help
>
> Ajay

[ Post a follow-up to this message ]